#include <iostream>
int main() {
std::cout << "Hello World!\n";
return 0;
}
Hello World!
You need g++
compiler from GNU Compiler Collection.
If you have no compiler on you computer, install it. Alternatively, you may try this
online development environment.
$ g++ hello.cpp
$ ./a.out
Hello World!
By default, the executable file is called a.out
, to give it a different name,
you can run the compiler with the option -o myname
, for example:
$ g++ -o hello hello.cpp
$ ./hello
Hello World!
#include <iostream>
using namespace std;
int main() {
int x = 10;
int y = 2 * x;
int z;
y = y * 5;
z = y - x - 20;
double pi = 3.14159265;
double proxima_centauri = 40100000000000000.0; // meters
double proxima_centauri2 = 4.01e+16; // 4.01 x 10^16
char c = 'A';
cout << x << endl;
cout << y << endl;
cout << z << endl;
cout << proxima_centauri << endl;
cout << c << " " << static_cast<int>(c) << endl;
return 0;
}
10
100
70
4.01e+16
A 65
#include <iostream>
using namespace std;
int main() {
// Integer operations
int x1 = 27 + 5; // addition
int x2 = 27 - 5; // subtraction
int x3 = 27 * 5; // multiplication
int x4 = 27 / 5; // quotient (integer division)
int x5 = 27 % 5; // remainder
int r = (x1 - x2) * x3 / (x4 + x5);
cout
<< x1 << " " << x2 << " " << x3 << " "
<< x4 << " " << x5 << " " << r << endl;
return 0;
}
32 22 135 5 2 192
#include <iostream>
using namespace std;
int main() {
// Floating-point operations
double y1 = 27.2 + 5.2; // addition
double y2 = 27.2 - 5.2; // subtraction
double y3 = 27.2 * 5.2; // multiplication
double y4 = 27.2 / 5.2; // division
double r = (y1 - y2) * y3 / (y4 + 1.0);
cout
<< y1 << " " << y2 << " " << y3 << " "
<< y4 << " " << r << endl;
return 0;
}
32.4 22 141.44 5.23077 236.083
#include <iostream>
using namespace std;
int main(){
// Conversion at assignment:
int i1 = 1;
int i2 = 2.5; // fractional decimal places are truncated
cout << i1 << " " << i2 << endl;
double d1 = i1; // auto conversion of int to double
cout << d1 << endl;
// Conversion before applying binary operators:
double d2 = 3 + 1.5; // int becomes double, then 3.0 + 1.5
double d3 = 1.5 + 3; // int becomes double, then 1.5 + 3.0
int i3 = 3 + 1.5; // 3 + 1.5 = 4.5, and then truncated to 4
cout << d2 << " " << d3 << " " << i3 << endl;
return 0;
}
1 2
1
4.5 4.5 4
#include <iostream>
using namespace std;
int main() {
int v = 25, w = 29, x = 30, y = 31, z = -31;
int d = 10;
double dd = 10.0;
cout
<< v/d << " " << w/d << " " << x/d << " "
<< y/d << " " << z/d << endl;
cout
<< v/dd << " " << w/dd << " " << x/dd << " "
<< y/dd << " " << z/dd << endl;
return 0;
}
2 2 3 3 -3
2.5 2.9 3 3.1 -3.1
#include <iostream>
using namespace std;
int main() {
int a = 40, b = 13;
int x = a / b; // integer division
double y = a / b; // integer division, then conversion
cout
<< x << " " << y << " " << endl;
// we can do explicit type conversion before division:
double z = a / static_cast<double>(b);
// or
double u = static_cast<double>(a) / b;
// or
double v = static_cast<double>(a) / static_cast<double>(b);
cout
<< z << " " << u << " " << v << endl;
}
3 3
3.07692 3.07692 3.07692
To increment a variable x
, you can write x = x + 1
. However, there is a shortcut increment operator for that:
you can write ++x
or x++
achieving the same effect. Similarly, you can use --x
or x--
to decrement x
.
Consider an example:
#include <iostream>
using namespace std;
int main() {
int x = 0;
cout << x << endl;
// to increment x
x++;
cout << x << endl;
// or
++x;
cout << x << endl;
// decrement x
x--;
cout << x << endl;
// or
--x;
cout << x << endl;
return 0;
}
0
1
2
1
0
However, notice the difference between the post-increment (x++
) and pre-increment (++x
).
They would return different values if used as an expression (not as a standalone statement). Consider:
#include <iostream>
using namespace std;
int main() {
// The difference between x++ and ++x
// (x++) as an expression returns the initial value of x
// i.e. it returns x, then increments it
int x = 10;
cout << 2 * (x++) << endl;
cout << x << endl;
// (++x) as an expression returns the incremented value
// i.e. it increments x, then returns it
int y = 10;
cout << 2 * (++y) << endl;
cout << y << endl;
return 0;
}
20
11
22
11
#include <iostream>
using namespace std;
int main() {
int num = 0;
cout << "Enter a number: ";
cin >> num;
if (num > 0) {
cout << "The number is positive." << endl;
}
else if (num == 0) {
cout << "The number is a zero." << endl;
}
else {
cout << "The number is negative." << endl;
}
return 0;
}
Enter a number: 10
The number is positive.